python 获取视频 文件分辨率和时长,性能最高是那种 ?
在 Python 中获取视频文件的分辨率和时长,有几种常见的方法。为了性能最高,可以考虑以下几种方法:
OpenCV: OpenCV 是一个非常流行的计算机视觉库,支持多种视频格式。它的性能通常较好,适合处理视频文件。
import cv2
def get_video_info_opencv(file_path):
cap = cv2.VideoCapture(file_path)
if not cap.isOpened():
return None
width = int(cap.get(cv2.CAP_PROP_FRAME_WIDTH))
height = int(cap.get(cv2.CAP_PROP_FRAME_HEIGHT))
fps = cap.get(cv2.CAP_PROP_FPS)
frame_count = int(cap.get(cv2.CAP_PROP_FRAME_COUNT))
duration = frame_count / fps
cap.release()
return width, height, duration
file_path = 'your_video_file.mp4'
info = get_video_info_opencv(file_path)
if info:
print(f"Resolution: {info[0]}x{info[1]}, Duration: {info[2]} seconds")
else:
print("Failed to get video info")
FFmpeg with subprocess:
FFmpeg 是一个强大的多媒体处理工具,可以通过命令行获取视频信息。使用 subprocess
模块调用 FFmpeg 命令,可以高效地获取视频信息。
import subprocess
import json
def get_video_info_ffmpeg(file_path):
cmd = [
'ffprobe', '-v', 'error', '-select_streams', 'v:0',
'-show_entries', 'stream=width,height,duration',
'-of', 'json', file_path
]
result = subprocess.run(cmd, stdout=subprocess.PIPE, stderr=subprocess.PIPE, text=True)
if result.returncode != 0:
return None
info = json.loads(result.stdout)
width = info['streams'][0]['width']
height = info['streams'][0]['height']
duration = float(info['streams'][0]['duration'])
return width, height, duration
file_path = 'your_video_file.mp4'
info = get_video_info_ffmpeg(file_path)
if info:
print(f"Resolution: {info[0]}x{info[1]}, Duration: {info[2]} seconds")
else:
print("Failed to get video info")
MoviePy: MoviePy 是一个用于视频编辑的库,虽然功能强大,但性能可能不如前两者。
from moviepy.editor import VideoFileClip
def get_video_info_moviepy(file_path):
clip = VideoFileClip(file_path)
width, height = clip.size
duration = clip.duration
clip.close()
return width, height, duration
file_path = 'your_video_file.mp4'
info = get_video_info_moviepy(file_path)
if info:
print(f"Resolution: {info[0]}x{info[1]}, Duration: {info[2]} seconds")
else:
print("Failed to get video info")
综合考虑,FFmpeg with subprocess 通常是性能最高的选择,特别是当你只需要获取视频的基本信息时。