帮我写一份python代码,用于在grasshopper中任意弯曲一条直线
当然可以!Grasshopper 是 Rhino 的一个可视化编程插件,主要用于参数化设计。虽然 Grasshopper 本身主要是通过图形界面进行操作,但你可以使用 Python 脚本来扩展其功能。
下面是一个简单的 Python 脚本示例,用于在 Grasshopper 中任意弯曲一条直线。这个脚本将使用 RhinoCommon 库来操作几何对象。
import Rhino.Geometry as rg
import random
def bend_line(line, num_points, max_deviation):
"""
Bends a straight line by adding random deviations to intermediate points.
Parameters:
line (rg.Line): The original straight line.
num_points (int): Number of intermediate points to add.
max_deviation (float): Maximum deviation for each point.
Returns:
rg.Curve: The resulting bent curve.
"""
# Create a list to store the points
points = []
# Add the start point of the line
points.append(line.From)
# Calculate the step size
step = 1.0 / (num_points + 1)
# Add intermediate points with random deviations
for i in range(1, num_points + 1):
t = i * step
point = line.PointAt(t)
deviation = rg.Vector3d(random.uniform(-max_deviation, max_deviation),
random.uniform(-max_deviation, max_deviation),
random.uniform(-max_deviation, max_deviation))
point += deviation
points.append(point)
# Add the end point of the line
points.append(line.To)
# Create a polyline from the points
polyline = rg.Polyline(points)
# Convert the polyline to a curve
curve = polyline.ToNurbsCurve()
return curve
# Example usage
# Input parameters
line = rg.Line(rg.Point3d(0, 0, 0), rg.Point3d(10, 0, 0)) # A straight line from (0,0,0) to (10,0,0)
num_points = 10 # Number of intermediate points
max_deviation = 1.0 # Maximum deviation for each point
# Call the function
bent_curve = bend_line(line, num_points, max_deviation)
# Output the result
a = bent_curve # 'a' is the output parameter in Grasshopper
bend_line
函数: 该函数接受一条直线、要添加的中间点数量和每个点的最大偏移量作为参数。bend_line
函数,最后将结果输出到 Grasshopper。将此代码粘贴到 Grasshopper 的 Python 脚本组件中,并连接相应的输入参数(如直线、点数和最大偏移量),你就可以看到一条弯曲的线了。